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The half life  of C-14 is 5600 years. A sample of freshly cut wood from a tree contains 10 mg of C-14. The amount left in the sample after 50000 years is (a-x) x 100 . The value of a-x×100 is

detailed solution


t =2.303Klogaa-x

K =0.693t1/2 = 0.6935600

logaa-x =5000×0.6935600×2.303

(a-x) = 0.02mg

(a-x)×100 = 0.02 ×100 =2mg

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