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Q.

The half-life of radioactive Polonium (Po) is 138.6 days. For ten lakh Polonium atoms, the number of disintegrations in 24 hours is (approx.)… 121138.6=0.995011

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a

4000

b

5000

c

2000

d

3000

answer is D.

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Detailed Solution

n = \frac{{24}}{{24 \times 138.6}} = \frac{1}{{138.6}};Now\,\,\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n} = {\left( {\frac{1}{2}} \right)^{1/138.6}}
\Rightarrow N = 10,00000{\left( {\frac{1}{2}} \right)^{1/138.6}} = 995011

So number of disintegrations

= 1000000 - 995011 = 4989 \approx 5000
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