The half-life of At 215 is 100μs. The time taken for the radioactivity of a sample of At 215 to decay to 1/16th of its initial value is

N=N02n⇒N016=N02n⇒n=4∴t=nT1/2=4(100)=400 μs.

The half-life of At 215 is 100μs. The time taken for the radioactivity of a sample of At 215 to decay to 1/16th of its initial value is

N=N02n⇒N016=N02n⇒n=4∴t=nT1/2=4(100)=400 μs.

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The half-life of ${}^{215}{At}$ is $100 μs$ . The time taken for the radioactivity of a sample of ${}^{215}{At}$ to decay to 1/16^th of its initial value is

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$400 μs$

$6.3 μs$

$40 μs$

$300 μs$

answer is A.

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$N = \frac{N_{0}}{2^{n}} \Rightarrow \frac{N_{0}}{16} = \frac{N_{0}}{2^{n}} \Rightarrow n = 4$

$∴ t = {nT}_{1 / 2} = 4 (100) = 400 μs .$

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The half-life of At 215 is 100μs. The time taken for the radioactivity of a sample of At 215 to decay to 1/16th of its initial value is

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The half-life of ${}^{215}{At}$ is $100 μs$ . The time taken for the radioactivity of a sample of ${}^{215}{At}$ to decay to 1/16^th of its initial value is