The half-life period of a substance is 1600 min. How much fraction of the substance will remain after 6400 min?

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1/4

1/16

1/8

1/2

answer is A.

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Detailed Solution

$t_{1 / 2} = 1600 \min, T = 6400 \min Number of half lives = \frac{6400}{1600} = 4 We know that N = {(\frac{1}{2})}^{n} N_{0} or \frac{N}{N_{0}} = {(\frac{1}{2})}^{n} = {(\frac{1}{2})}^{4} = \frac{1}{16}$

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