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Q.

The half-life periods of two first-order reactions are in the ratio 3: 2. If t1 is the time required for 25% completion of the first reaction and t2 is the time required for 75% completion of the second reaction, then the ratio, t1 : t2, is (log 3 = 0.48, log 2 = 0.3)

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a

3 : 5

b

3 : 2

c

3 : 10

d

12 : 25

answer is A.

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Detailed Solution

t1t2=t1/21log⁡2log⁡10075t1/22log2⋅log⁡10025=t1/21log⁡43t1/22log⁡(4)=32×0.6−0.480.6=310

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