The handle of a door is at a distance 40cm from axis of rotation. If a force 5N is applied on the handle in a direction 30⁰ with plane of door, then the torque is

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. The torque due to a force F is given as 

$\left|\mathrm{\tau }\right|=\mathrm{rFsin} \mathrm{\theta }=5\mathrm{N}\times 0.4\mathrm{m}\times \sin {30}^{°}=1\mathrm{Nm}$

Hence the correct answer is 1Nm.