The Hardness of water due to $H C O_{3}^{-}$ is 122ppm. Select the correct statement(s)

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The hardness of water in terms of $C a C O_{3}$ is 100ppm

The hardness of water in terms of $C a C l_{2}$ is 222ppm

The hardness of water in terms of $M g C l_{2}$ is 95ppm

The hardness of water in terms of $C a C O_{3}$ is 200ppm

answer is B, D.

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Detailed Solution

Since 2 mol of $H C O_{3}^{-}$ is present. SO there should be One mole each of $C a C O_{3}, C a C l_{2}$ and $M g C l_{2}$ to have equal hardness.
$\begin{array}{l} M w o f H C O_{3}^{-} = 61, \\ p p m o f H C O_{3}^{-} = 61 \times 2 = 122 g i n 10^{6} m L H_{2} O \\ [M w o f C a C O_{3} = 100, M w o f C a C l_{2} = 111, M w o f M g C l_{2} = 95 m o l^{- 1}] \\ 1 m o l o f C a C O_{3} = 100 p p m \\ 1 m o l o f C a C l_{2} = 111 p p m \\ 1 m o l o f M g C l_{2} = 95 p p m \end{array}$
Hence, answer is(b) and (d)