The Harmonic mean of the numbers 2, 3, 4 is

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$\frac{13}{36}$

$\frac{36}{13}$

$\sqrt[3]{24}$

answer is D.

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Detailed Solution

$\begin{array}{rcl} 2, 3, 4 \\ H . M & = & \frac{3}{\frac{1}{2} + \frac{1}{3} + \frac{1}{4}} \\ = & \frac{3}{\frac{6 + 4 + 3}{12}} \\ = & \frac{36}{13} \end{array}$

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