The HCF of each pair of three numbers is 15 and the LCM of all the three numbers is 1890. Then the product of the numbers is

Let $a=15k_1,b=k_2,c=15k_3$

$\text{L.C.M of }(a,b,c)=15k_1{k}_2{k}_3=1890$

$\text{H.C.F of}(a,b)=15[\therefore (k_1,k_2)=1(k_2,k_3)=1\left(k_{1,}{k}_3\right)=1]$

Product of three numbers $=\left(\text{L.C.M of three numbers}\right)\times H.C.Fof(a,b),(b,c)(c,a)$

$15k_1\times 15k_2\times 15k_3=15\times 15\times 15k_1{k}_2{k}_3$

$\Rightarrow 225\times 1890=425250$