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Q.

The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, then find the other number.


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a

207

b

205

c

230

d

203 

answer is A.

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Detailed Solution

Given that HCF of two numbers is 23 and their LCM is 1449 and one of the numbers is 161.
We know that the product of the HCF and LCM of any two numbers is always equal to the product of the numbers itself, i.e.,
HCF × LCM = Product of the numbers.
Let us assume the other number to be x.
Then we have,
161×x=23×1449 x= 23×1449 161 x=23×9 x=207
So, the other number is 207.
Hence, the correct option is (1).
 
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