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The H.C.F of $42$ , $63$ and $140$ is

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9

7

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answer is D.

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Detailed Solution

$42 = 2 \times 3 \times 7$

$63 = 3^{2} \times 7$

$140 = 2^{2} \times 5 \times 7$

H.C.F of 42, 63 and $140 = 7$

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