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The heart of a man beats 80 times a minute. What is its frequency?

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$2.25 s^{- 1}$

$1.33 s^{- 1}$

$1.2 s^{- 1}$

$1.29 s^{- 1}$

answer is B.

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Detailed Solution

Given: t=80 times in a minute

1 minute = 60 seconds

So in 60 seconds, the heartbeat = 80 times

Number of heartbeats = Number of cycles = 80

$F r e q u e n c y (f) = \frac{n o . o f c y c l e s}{t i m e i n s e c o n d s}$

$f = 80 / 60 = 1.33 s^{- 1}$

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