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Q.

The heat capacity of liquid water is 75.6J/mol K,, while the enthalpy of fusion of ice is 6.0 kJ/mol. What is the smallest number of ice cubes at O∘C, each containing 9.0 g  of water, needed to cool 500 g of liquid water from 20∘C to O∘C ?

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a

7

b

1

c

14

d

none of these

answer is C.

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Detailed Solution

Heat released by water =50018×75.6×20

Let n number of cubes are required.

So, n×918×6000=50018×75.6×20

     n=14.

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