The heat of atomization of methane and ethane are 360 kJ/mol and 620 kJ/mol, respectively. The longest wavelength of light capable of breaking the C-C bond is:
(Avogadro number $= 6.02 \times 10^{23}, h = 6.62 \times 10^{- 34} Js$ )

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$1.49 \times 10^{3} nm$

$2 .48 \times 10^{4} nm$

$2 .48 \times 10^{3} nm$

$1.49 \times 10^{4} nm$

answer is A.

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Detailed Solution

The bond energy of the C-H bond is,
$\begin{array}{l} {BE}_{C - H} = \frac{360}{4} = 90 \\ {BE}_{C - C} = 620 - 6 \times 90 = 80 kJ / mol \\ 80 \times 10^{3} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{λ} \times 6.02 \times 10^{23} \\ \Rightarrow λ = 1.49 \times 10^{- 6} m = 1.49 \times 10^{3} nm \end{array}$