Q.

The heat of combustion of benzene at 27°C found by bomb calorimeter i.e. for the reactionC6H6(l)+712O2(g)6CO2(g)+3H2O(l)is 780 K.Cal mol–1. The heat evolved on burning 39g of benzene in an open vessel wil be

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a

780.9 K.Cal

b

390 K.Cal

c

390.45 K.Cal

d

780 K.Cal

answer is C.

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Detailed Solution

H=E+ngRT

= - 780 + (-1.5)×2×10-3×300 = -780.9 Kcal

heat evolved = 780.9×3978 = 390.45 KCal

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