The heat of combustion of $H_2$, graphite and sugarcane are -68.4 Kcal, -94.4 Kcal and -1350 Kcal / more respectively calculate heat of formation of cane sugar? 

 $\left(1\right)H_{2\left(g\right)}+\frac{1}{2}{O}_{2\left(g\right)}\to H_2{O}_{\left(g\right)};\Delta H=-68.4Kcal$
 $\begin{array}{l}\left(2\right)C_{\left(S\right)}+O_{2\left(g\right)}\to C{O}_{2\left(g\right)};\Delta H=-94.4Kcal\\ \left(3\right)C_{12}{H}_{22}{O}_{11}\left(S\right)+12O_{2\left(g\right)}\to 12C{O}_{2\left(g\right)};\Delta H=-1350Kcal\end{array}$
Required equation is
$12C_{\left(S\right)}+11H_{2\left(g\right)}+\frac{11}{2}{O}_2\to C_{12}{H}_{22}{O}_{11}$ 
 
$\begin{array}{l}(-94.4\times 12)+(-68.4\times 11)+1350\\ =-535.2Kcal\end{array}$