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Q.

The heat of combustion of solid benzoic acid at constant volume is – 321.30 KJ at 270C. The heat of combustion at constant pressure is

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a

-321.30 + 900 R.

b

-321.30 – 300 R

c

-321.30 + 300 R

d

-321.30 – 150 R

answer is C.

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Detailed Solution

\large {C_6}{H_5}COO{H_{(s)}}\; + \;\frac{{15}}{2}{O_2}_{_{(g)}}\; \to \;7C{O_{{2_{(g)}}}}\; + \;3{H_2}{O_{(l)}}\

 


 

Δn(g) = 7-15/2 = -1/2
ΔH = ΔE + Δn(g) RT = -321.30+(-1/2)R x 300

= -321.30-150R

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