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Q.

The heat of formation ofC2H5OH(l) is -66 kcal/mole. The heat of combustion of CH3OCH3(g) is -348 kcal/mole. ΔHf for H2O(l) and CO2 (g) are -68 kcal/mole and-94 kcal/mole respectively. Then the ΔH for the isomerisation reaction,

C2H5OH(l)CH3OCH3(g) and ΔE for the same are : (Take : Tsurr =298K)

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a

ΔH=22 kcal/mole, ΔE=21.404 kcal/mole

b

ΔH=18 kcal/mole, ΔE=17.301 kcal/mole

c

ΔH=26 kcal/mole, ΔE=25.709 kcal/mole

d

ΔH=30 kcal/mole, ΔE=28.522 kcal/mole

answer is B.

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Detailed Solution

CH3OCH3(g)+3O2(g)2CO2(g)+3H2O(l) 348=68×394×2ΔHf ΔHf=44

C2H5OH(l)CH3OCH3(g)ΔHRxn=44+66=+22 kcal/moleΔE=ΔHΔngRT=221×2×2981000=21.404 kcal/mol

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