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The heat of neutralization between weak acid (HCN) and strong base (NaOH) is (-56.1) kJ/mol. The neutralization between strong acid (HCI) and strong base (NaOH) is (-57.3) k.J/mol. If the weak acid (HCN) is 80% ionized in the above solution then calculate the heat of ionization (in J/mol) for 100% ionization of HCN in the above solution.

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Detailed Solution

Total neutralization,

$\begin{array}{l} - 56.1 + 57.3 = 1.2 kJ / mol \\ 80 % \to 1.2 \\ 100 % \to \frac{1.2}{0.8} = 1.5 \end{array}$

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