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Q.

The height of a mercury barometer is 75 cm at sea level and 50 cm at the top of a hill. Ratio of density of mercury to that of air is 10⁴. The height of the hill is

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a

750 m

b

250 m

c

2.5 km

d

1.25 km

answer is B.

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Detailed Solution

$Δp = (h_{1} - h_{2}) \times ρ_{Hg} \times g = h \times ρ_{air} \times g$

$\Rightarrow h = (h_{1} - h_{2}) \times \frac{ρ_{Hg}}{ρ_{air}} = (0.75 - 0.50) \times 10^{4} = 2500 m$

$\Rightarrow h = 2.5 k m$

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