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The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be : (Given g = acceleration due to gravity at the surface of earth)

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$\frac{g}{9}$

$\frac{g}{4}$

$\frac{g}{2}$

$\frac{g}{3}$

answer is D.

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Detailed Solution

$g = \frac{Gm}{r^{2}}$

$g' = \frac{Gm}{(3 r^{2})}$

$g' = \frac{Gm}{9 r^{2}}$

$g' = \frac{g}{9}$

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