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The height of liquid column raised in a capillary tube of certain radius when dipped in liquid A vertically is 5cm. If this tube is immersed vertically in another liquid B of surface tension and density double the values of liquid A, the height of liquid column raised in liquid B would be …. m (Assume angle of contact remains same in both the cases)

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0.10

0.05

0.20

0.5

answer is B.

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Detailed Solution

$T = \frac{rh ρ g}{2 \cos θ} \Rightarrow h \propto \frac{T}{ρ}$

$\frac{h_{1}}{h_{2}} = \frac{T_{1}}{T_{2}} \times \frac{ρ_{2}}{ρ_{1}}$

$\frac{5}{h_{2}} = \frac{T}{2 T} \times \frac{2 ρ}{ρ}$

$\frac{5}{h_{2}} = \frac{1}{2} \times \frac{2}{1}$

$h_{2} = 5 c m = 0.05 m$

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