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Q.

The Henry’s law constant for O2 dissolved in water is 4.34×104 atm at certain temperature.  If the partial pressure of O2 in a gas mixture that is in equilibrium with water is 0.434 atm, what is the mole fraction of O2 in solution?

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a

1×105

b

1×104

c

2×105

d

2×106

answer is A.

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Detailed Solution

According to Henry’s law, P=KH×x

XO2=PO2KH=0.4344.34×104=1×105

Mole fraction of O2 in water =1×105.

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The Henry’s law constant for O2 dissolved in water is 4.34×104 atm at certain temperature.  If the partial pressure of O2 in a gas mixture that is in equilibrium with water is 0.434 atm, what is the mole fraction of O2 in solution?