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The horizontal and vertical components of the velocity of a projectile are $10 m / s$ and $20 m / s$ , respectively. The horizontal range of the projectile will be $[g = 10 m / s^{2}]$

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$5 m$

$10 m$

$20 m$

$40 m$

answer is D.

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Detailed Solution

$R = \frac{2 u_{x} u_{y}}{g} R = \frac{2 \times 10 \times 20}{10} R = 40 m$

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