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Q.

The horizontal component of the earth’s magnetic field at a place is 3×104T  and the dip is  θ=tan1(4/3). A metal rod of length 0.25 m placed in the north-south position is moved at a constant speed of 10 m/s towards the east. The e.m.f induced in the rod will be _____mV.

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Detailed Solution

tanθ=BVBH

BV=3×10-4T×43=4×10-4T

e=BVlv =4×10-4×0.25×10=1mV

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