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Q.

The horizontal component of the earth’s magnetic field at a certain place is 2.6×10-5T and the angle of dip is 60°. What is the magnetic field of the earth at this location?

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Detailed Solution

cos⁡θ=HB⇒B=Hcos⁡60=2.6×10−512=5.2×10−5T

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The horizontal component of the earth’s magnetic field at a certain place is 2.6×10-5T and the angle of dip is 60°. What is the magnetic field of the earth at this location?