The horizontal force required to move a plate of area 2 m2 with a velocity of 4.5 ms-1 when it rests on a layer of oil 2 mm thick (coefficient of viscosity of oil is 2 Ns m-2)

F=ηAΔVΔx=2×2×4.52×10−3=9×103=9000 N

The horizontal force required to move a plate of area 2 m2 with a velocity of 4.5 ms-1 when it rests on a layer of oil 2 mm thick (coefficient of viscosity of oil is 2 Ns m-2)

F=ηAΔVΔx=2×2×4.52×10−3=9×103=9000 N

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The horizontal force required to move a plate of area 2 m² with a velocity of 4.5 ms^-1 when it rests on a layer of oil 2 mm thick (coefficient of viscosity of oil is 2 Ns m^-2)

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900 N

9000 N

0.9 N

1000 N

answer is B.

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$F = η A \frac{Δ V}{Δ x} = 2 \times 2 \times \frac{4.5}{2 \times 10^{- 3}} = 9 \times 10^{3} = 9000 N$

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The horizontal force required to move a plate of area 2 m2 with a velocity of 4.5 ms-1 when it rests on a layer of oil 2 mm thick (coefficient of viscosity of oil is 2 Ns m-2)

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The horizontal force required to move a plate of area 2 m² with a velocity of 4.5 ms^-1 when it rests on a layer of oil 2 mm thick (coefficient of viscosity of oil is 2 Ns m^-2)