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Q.

The horizontal range and maximum height attained by a projectile are R and H, respectively. If a constant horizontal acceleration a= g/4 is imparted to the projectile due to wind, then its horizontal range and maximum height will be

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a

(R+H),H2

b

R+H2,2H

c

(R+2H),H

d

(R+H),H

answer is D.

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Detailed Solution

detailed_solution_thumbnail

H=u2sin2⁡θ2g,R=u2sin⁡2θg

Maximum height will be same because acceleration
a = g/4 is in horizontal direction

R′=ucos⁡θT+12aT2=R+12g42usin⁡θg2=R+H

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