Q.

The horizontal range of a projectile is R and the maximum height attained by it is H. A force now begins to act on the projectile, giving it a constant horizontal acceleration  =g/2. Under the same conditions of projection, the new horizontal range of the projectile is  R' then the value of R'RH  is 

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answer is 2.

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Detailed Solution

R=u2sin2θg,H=u2sin2θ2g

R'=ucosθ(2using)+12(g2)(2usinθg)2

R'=R+u2sin2θg

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The horizontal range of a projectile is R and the maximum height attained by it is H. A force now begins to act on the projectile, giving it a constant horizontal acceleration  =g/2. Under the same conditions of projection, the new horizontal range of the projectile is  R' then the value of R'−RH  is