The human body requires $2370\mathrm{ }\mathrm{K}$. Cal of energy daily. The heat of combustion of glucose is $-790\mathrm{ }\mathrm{K}$. cal/mole. The amount of glucose required for daily consumption is

Given data: To find the amount of glucose required for daily consumption Formula / Concept used: Thermodynamic processes - Heat of combustion Detailed solution:

The expression for finding moles when the heat of combustion is given is

 no. of moles = Energy in $\frac{Kcal}{\text{ heat }}$ of combustion $=\frac{2370}{790}=3$

 3 moles of glucose are required daily

 The molecular weight of glucose is 180

 $n=\frac{w}{MW}$

 $3=\frac{w}{180}=3\times 180=540$

540g of glucose is required daily.

Hence the correct option is (B).