The human body requires 2370 K. Cal of energy daily. The heat of combustion of glucose is -790 K. cal/mole. The amount of glucose required for daily consumption is

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The human body requires $2370 K$ . Cal of energy daily. The heat of combustion of glucose is $- 790 K$ . cal/mole. The amount of glucose required for daily consumption is

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$540 g$

$327 g$

$490.5$

$650 g$

answer is B.

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Detailed Solution

Given data: To find the amount of glucose required for daily consumption Formula / Concept used: Thermodynamic processes - Heat of combustion Detailed solution:

The expression for finding moles when the heat of combustion is given is

no. of moles = Energy in $\frac{K c a l}{heat}$ of combustion $= \frac{2370}{790} = 3$

3 moles of glucose are required daily

The molecular weight of glucose is 180

$n = \frac{w}{M W}$

$3 = \frac{w}{180} = 3 \times 180 = 540$

540g of glucose is required daily.

Hence the correct option is (B).

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