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The human eye has an approximate angular resolution of $ϕ = 5.8 \times 10^{- 4}$ rad and a typical photo-printer prints a minimum of 300 dpi (dots per inch, 1inch = 2.54cm). At what minimum distance z (in cm) should a printed page be held so that one does not see the individual dots?

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44.1

14.7

37.3

answer is D.

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Detailed Solution

d = Distance between adjacent dots= $\frac{2.54}{299}$

$∆ θ = \frac{d}{D}; D = \frac{d}{∆ θ} = \frac{\frac{2.54}{299}}{5.8 \times 10^{- 4}} D = \frac{254 \times 10^{4}}{580 \times 299}$ =14.64cm

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