Q.

The hybridisation of iron in K4[Fe(CN)6] is

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a

sp3

b

d2sp3

c

sp3d2

d

dsp2

answer is C.

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Detailed Solution

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  • Iron(Fe) is atomic no 26.
  • In which 6 electrons are in 3d orbitals and 2 electrons are there in 4s orbital.
  • In this complex, it exists in +2 oxidation state. When ligands CN  approach to the central metal atom, the electrons remains in the inner orbital. 
  • And 6 electron pairs of 6CN are filled in 2d,1s and 3p orbitals. 
  • Hence the Hybridisation is d2sp3
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