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The hybridisation of silicon in ${SiO}_{4}^{4 -}$ is

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${sp}^{2}$

${sp}^{3} d$

${sp}^{3}$

answer is C.

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Detailed Solution

(a) Tetrahedral structure of the $\mathrm{SiO_4^{4-}}$ $SiO$ $44$ $-$ $$ anion.
(b) Representation of the $\mathrm{SiO_4}$ $SiO$ $4$ $$ unit.
Legend: solid dot = Silicon, open circles = Oxygen.

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