The hybridization in ${AB}_{6} E$ molecule is

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${Sp}^{3}$

${Sp}^{3} d^{2}$

${Sp}^{3} d^{3}$

${Sp}^{3} d$

answer is B.

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Detailed Solution

The molecule ${AB}_{6} E$ type has total 6 bond pairs and 1 lone pair around the central atom with distorted pentagonal bipyramidal geometry. Hybridization of central atom is ${Sp}^{3} d^{3}$ $EX; {XeF}_{6}$

${Sp}^{3} d^{3},$ distorted pentagonal bipyramidal.

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