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The hybridization of ‘Be’ in ${BeCl}_{2}$ in the polymeric solid state, vapour phase and monomeric linear molecule respectively is

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${sp, sp}^{2}, {sp}^{3}$

${sp}^{3} {, sp}^{2}, sp$

${sp}^{2} {, sp, sp}^{3}$

${sp}^{3} {, sp}^{3}, sp$

answer is B.

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Detailed Solution

BeCl₂…. 2bp…..sp ;

In dimeric state each ‘Be’ atom is attached to three ‘Cl’ atoms….sp²;

In polymeric state each ‘Be" atom is attached to four ’Cl' atoms…sp³ ;

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