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The hybridization of carbon atom (1) and carbon atom (2) in the following compound are $N \equiv C - C H = C H_{2}$ respectively

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$s p^{2} & s p^{2}$

$s p^{3} & s p$

$s p & s p^{2}$

$s p & s p$

answer is C.

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Detailed Solution

$N \equiv \underset{1}{C} - \underset{2}{C H} = \underset{3}{C H_{2}}$

Sp and sp²

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