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The hybridization of central carbon atom in (CH₃)₃ $\dot{C}$ is

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sp²

sp³

dsp²

answer is B.

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Detailed Solution

In free radicals, the odd electron containing carbon mainly undergoes sp² hybridisation and around the radical carbon trigonal planar shape is present.

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3σ bonds with unpaired electron

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Sp² hybridisation with out lone pair

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Trigoanl planar shape

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