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The hybridization of ‘O’ in $H_{2} O$ is

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${SP}^{2}$

${SP}^{3}$

$SP$

${SP}^{3} d$

answer is B.

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Detailed Solution

The hybridization of ‘O’ in $H_{2} O$ is 𝑠𝑝ଷ because one 2s orbital and three 2p orbitals of oxygen are involved in 𝑠𝑝ଷ hybridization to form four equal and identical ${sp}^{3}$ hybrid orbitals with equal size, shape and energy.

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