The hybridization of ‘O’ in ${\mathrm{H}}_2\mathrm{O}$  is

The hybridization of ‘O’ in ${\mathrm{H}}_2\mathrm{O}$  is 𝑠𝑝ଷ because one 2s orbital and three 2p orbitals of oxygen are involved in 𝑠𝑝ଷ hybridization to form four equal and identical ${\mathrm{sp}}^3$  hybrid orbitals with equal size, shape and energy.