The hybridization of oxygen in ${\mathrm{OF}}_2$ molecule is

Oxygen has 6 electrons in its valence shell because it has an atomic number of 8 and an electronic configuration of 2,6. The remaining four electrons generate 2 lone pairs and two bonds with fluorine.

In ${\mathrm{OF}}_2$, oxygen has 2 bond pairs and 2 lone pairs and hence hybridization is ${\mathrm{sp}}^3$

Hence, the correct option is  (C).