The hybridization of oxygen in ${OF}_{2}$ molecule is

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${sp}^{2}$

${sp}^{3}$

${dsp}^{2}$

answer is C.

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Detailed Solution

Oxygen has 6 electrons in its valence shell because it has an atomic number of 8 and an electronic configuration of 2,6. The remaining four electrons generate 2 lone pairs and two bonds with fluorine.

In ${OF}_{2}$ , oxygen has 2 bond pairs and 2 lone pairs and hence hybridization is ${sp}^{3}$

Hence, the correct option is (C).

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