The hybridization of P in ${PO}_{4}^{3 -}$ is same as in

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N in ${NO}_{3}^{-}$

I in ${ICl}_{4}^{-}$

S in SO₃

S in ${SO}_{4}^{2 -}$

answer is D.

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Detailed Solution

No. of hybrid orbitals(H.O)=1/2(No. of valence electrons on central atom + no. of monovalent atoms- Charge)

${PO}_{4}^{3 -}$ : no. of hybrid orbitals= 1/2(5+3)=4 --- sp³ hybridization

${ICl}_{4}^{-}$ : no. of hybrid orbitals= 1/2(7+4+1)=6 --- sp³d² hybridization

SO₃ : no. of hybrid orbitals= 1/2(6)=3 --- sp² hybridization

${NO}_{3}^{-}$ : no. of hybrid orbitals= 1/2(5+1)=3 --- sp² hybridization

${SO}_{4}^{2 -}$ : no. of hybrid orbitals= 1/2(6+2)=4 --- sp³ hybridization

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