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Q.

The hybridization of the atomic orbitals of Nitrogen in $N {O_{2}}^{-}, N {O_{2}}^{+} a n d N {H_{4}}^{\oplus}$ respectively are

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a

$s p^{3}, s p^{2} a n d s p$

b

$s p^{3}, s p a n d s p^{2}$

c

$s p^{2}, s p a n d s p^{3}$

d

$s p, s p^{2} a n d s p^{3}$

answer is B.

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Detailed Solution

$N {O_{2}}^{-} \to S P^{2} N {O_{2}}^{+} \to S P N {H_{4}}^{+} \to S P^{3}$

Hybridization $= \frac{1}{2} [V + M - c + a]$

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