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Q.

The hybridization of $S$ in $S {O_{4}}^{2 -}$ is same as in

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a

$C$ in $C {O_{3}}^{2 -}$

b

$As$ in $As {F_{4}}^{-}$

c

$S$ in $S {O_{3}}^{2 -}$

d

$Xe$ in ${XeF}_{4}$

answer is B.

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Detailed Solution

$S {O_{4}}^{2 -}$ is ${sp}^{3}$

Question Image

${XeF}_{4} \to {sp}^{3} d^{2} C {O_{3}}^{2 -} \to {sp}^{2} As {F_{4}}^{-} \to {sp}^{3} d$

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