The hydrated salt ${Na}_{2} {CO}_{3} \cdot {xH}_{2} O$ under goes 63% loss in mass on heating and becomes anhydrous. The value of ''x of is

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answer is 10.

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Detailed Solution

$\begin{array}{l} 100 gr {Na}_{2} {CO}_{3} \cdot {xH}_{2} O - 63 {grH}_{2} O \\ 106 + 18 xgr {Na}_{2} {Na}_{2} {CO}_{3} {xH}_{2} O - 18 {xgrH}_{2} O \\ \frac{106 + 18 x}{100} = \frac{18 x}{63} \Rightarrow x = 10 \end{array}$

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