The hydration of propyne in presence of $d i l . H_{2} S O_{4} / d i l . H g S O_{4}$ results in formation of

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Propene

propan-1-ol

Propanal

propanone

answer is B.

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Detailed Solution

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The hydration of an alkyne in the presence of dilute sulfuric acid and mercuric sulfate typically leads to the formation of a ketone via an intermediate enol, which rearranges to the more stable ketone.

Propyne (CH₃C≡CH), when hydrated, follows the Markovnikov rule, meaning that the -OH group will attach to the carbon with the most hydrogen atoms (the less substituted carbon of the alkyne), while the -H will add to the more substituted carbon.

This results in the formation of propanone (CH₃COCH₃), a ketone, after the initial formation of an enol intermediate, which tautomerizes to the more stable ketone.

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