The hydride ion H^- is stronger base than its hydroxide ion OH^-. Which of the following reactions will occur if sodium hydride (NaH) is dissolved in water?

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$2 H^{+} (aq) ⟶ H_{2} + 2 e^{-}$

$H^{-} + H_{2} O (l) ⟶ No reaction$

None of the above

$H^{+} (aq) + H_{2} O (l) ⟶ {OH}^{-} + H_{2}$

answer is B.

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Detailed Solution

Sodium hydride (NaH) exists as ${Na}^{+} and H^{-} .$ Hydride ion (acts as a base) and when it dissolve in water, then water acts as acid. The reaction that takes place in water after the addition of NaH is:

$H^{-} + H_{2} O \to {OH}^{-} + H_{2}$

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