The hydride that is not electron deficient is

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$B_{2} H_{6}$

${AlH}_{3}$

${SiH}_{4}$

${GaH}_{3}$

answer is C.

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Detailed Solution

Diborane (B₂H₆) is an electron-deficient molecule. Usually, 14 valence electrons required for the formation of eight bonds. But in diborane, 12 valence electrons form eight bonds in which each boron contributes three valence electrons and each hydrogen contributes one valence electron.

In AlH₃, there are six electrons in which three electrons contributed by Al and each hydrogen contributes one valence electron. As AlH₃ has incomplete octet, therefore it is known as electron deficient specie.

Si has four valence electrons and form four covalent bonds with four hydrogen atoms. Octet of Si in SiH₄ is also complete. Therefore, SiH₄ is not electron deficient.

In GaH₃, Ga shares three valence electrons and each hydrogen shares one electron. There are a total of six electrons in GaH₃ instead of 8. Therefore, GaH₃ is electron deficient.

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