The hydrogen electrode is dipped in a solution of pH = 3 at 25^oC. The potential of the cell would be (value of 2.303 RT/F is 0.059 V)

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0.059 V

0.087 V

– 0.177 V

0.177 V

answer is C.

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Detailed Solution

Complete Solution:

The potential of the hydrogen electrode (standard hydrogen electrode) in a solution of pH = 3 at 25°C can be calculated using the Nernst equation:

E = E⁰ - 0.059 V × pH

Since the standard potential E⁰ of the hydrogen electrode is 0 V:

E = 0 - (0.059 V) × 3

E = -0.177 V

Final Answer:

The potential of the cell is -0.177 V.

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