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The hydrogen halide which shows peroxide effect in its reaction with alkenes is

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HCl

HBr

answer is B.

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Detailed Solution

Bond dissociation enthalpy of H-F and H-Cl is very high.

They cannot undergo homolysis in presence of peroxide and thus cannot form free radicals.

Bond dissociation enthalpy of H-Br and H-I is comparatively low.

They can undergo homolysis in presence of peroxide and form free radicals.

But the larger $\overset{∙}{I}$ (Iodine free radical) formed instead of attacking alkene combines with another $\overset{∙}{I}$ (Iodine free radical) to form I₂.

Thus only HBr shows peroxide effect.

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