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Q.

The hydrolysis constant of MX is (Given, Kb  of MOH is 2×106  and Ka  of HX is 5×107 )

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a

102

b

102

c

103

d

103

answer is B.

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Detailed Solution

Kh=KwKaKb

      =1.0×10142×106×5×107

      =102

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The hydrolysis constant of MX is (Given, Kb  of MOH is 2×10−6  and Ka  of HX is 5×10−7 )