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The hydroxide ion concentration of a solution is 8 x 10 ^-11 M . What is the pH of the solution?
(log8=0.9030)

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2.10

2.9

3.9

4.9

answer is C.

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Detailed Solution

$p^{OH} = - \log_{10} [{OH}^{-}] = - \log [8 \times 10^{- 11}] = 11 - \log 8 = 11 - 0.903 = 10.097 P^{H} = 14 - P^{OH} = 14 - 10.097 = 3.9$

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